The text I am reading says:

Global variables are located in executable image, so using number of global variables will increase the size of executable image.

Questions:

1. What does 'located in executable image' mean? From what I have read the global variables are located in the 'data' section of the executable. I presume that local variable initialisation instructions are stored in the 'text' section. So why don't the local variable initialisation instructions take up about the same amount of space as the global variables do?

2. By executable, does it mean here the executable loaded into the memory or the executable that is only on the non-volatile memory? Will the global variables also take up more space for executable that is not loaded into the RAM?

3. Are there books or concise reading resources I may refer to that will help me with such lower level concepts?

I expected the size of the local variable initialization instructions to take up the same amount of space in executable as global variables do. Consider the following program:

#include <stdlib.h>

int global_var = 10

int main(void){

    int local_var = 20;
    return EXIT_SUCCESS;
}

When converted to machine level executable (assuming its not loaded into memory/not a process), I assume both definition and initialisation of global_var and local_var will be encoded as machine level code, albeit in different sections (data and text) of executable. So why will global_var take up more space?